15 men can complete a work in 8 days while 10 women can complete the same work in 20 days. 7 men starts working and after 12 days they are replaced by 10 women. Find time taken by 10 women to complete the remaining work.
Answers
Answer:
6 days
Step-by-step explanation:
Let the complete work is 1.
15 men do that in 8 days.
1 men do 1/120 part of work in 1 day
7 men do 7/120 part of work in 1 days
7 men do 84/120 part of work in 12 days
remaining work is (1- 84/120)=36/120=6/20
again 10 women do that in 10 days
10 women do 1/20 part of work in 1 day.
1/20 part of work done in 1 day
1 part of work done in 1*20=20 days
so, 6/20 part of work done in 6/20*20=6 days.
so answer is 6 days
The answer is 6 days.
GIVEN
15 men can complete a work in 8 days while 10 women can complete the same work in 20 days. 7 men starts working and after 12 days they are replaced by 10 women.
TO FIND
Time taken by 10 women to complete the remaining work.
SOLUTION
We can simply solve the above problem as follows;
It is given that,
15 men can complete work in 8 days.
So,
Number of days taken by 1 man to complete the work = 15 × 8 = 120 days
And,
10 women can do work in 20 days.
So,
Number of days taken by 1 woman = 20 × 10 = 200 days
Taking the LCM of the number of days taken by man and woman
LCM of 120 and 200 = 600
Efficiency of Man = 600/120 = 5
Efficiency of woman = 600/200 = 3
Let the time taken by 10 women to do the remaining work = t days
Amount of work done by 7 men in 12 days = (7×5) × 12 unit
Amount of work done by 10 women in t time = (10×3)×t
Total work = 600 units
So,
(7×5 × 12) + (10×3×t) = 600
420 + 30t = 600
30t = 600-420
30t = 180
t = 180/30
t = 6 days
Hence, The answer is 6 days.
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