Question

15 metre long 30 cm high is made up of bricks is measuring 22 cm into 12.5 cm into 7.5 CM if one by 12th of the volume of was consist of motor how many bricks are there in the wall

Answer 1

Step-by-step explanation:

The dimensions of the wall are

Length = 15m

Breadth = 0.3m

Height = 4m

We know that

Volume of the wall = l × b × h

By substituting the values

Volume of the wall = 15 × 0.3 × 4

So we get

Volume of the wall = 18 m3

It is given that the wall consists of 1/12 mortar

So we get

Volume of mortar = 1/12 × 18

By division

Volume of mortar = 1.5 m3

So the volume of wall = Volume of wall – Volume of mortar

By substituting the values

Volume of wall = 18 – 1.5

By subtraction

Volume of wall = 16.5 m3

The dimensions of the brick are

Length = 22cm = 0.22 m

Breadth = 12.5 cm = 0.125 m

Height = 7.5cm = 0.075 m

We know that

Volume of one brick = l × b × h

By substituting the values

Volume of one brick = 0.22 × 0.125 × 0.075

So we get

Volume of one brick = 0.0020625 m3

So the number of bricks = Volume of bricks/ Volume of one brick

By substituting the values

Number of bricks = 16.5/0.0020625

So we get

Number of bricks = 8000

Therefore, the number of bricks in the wall are 8000.

Answer 2

GivEn:

• 15 metre long 30 cm wide and 4 m high is made up of bricks is measuring 22 cm into 12.5 cm into 7.5 CM if one by 12th of the volume of was consist of mortar.

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To find:

• Number of bricks in the wall.

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SoluTion:

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${\underline{\bf{\bigstar\;As\;per\:given\;question\;:}}}$

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$\bf Dimensions_{\;(wall)} = \begin{cases} & \text{Length = 15 m } \\ & \text{Breadth = 30 cm = 0.3 m} \\ & \text{Height = 4 m} \end{cases}$

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Wall is in cuboidal shape.

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So, As we know that,

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$\star{\boxed{\sf{\purple{Volume\;of\;cuboid = l \times b \times h}}}}$

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$\;\;\;\;\;\;\;\small\sf \underline{Putting\;values\;:}$

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$:\implies\sf Volume_{\;(wall)} = 15 \times 0.3 \times 4$

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$:\implies\bf Volume_{\;(wall)} = 18\;m^3$

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Given that,

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Wall consist of 1/12 mortar.

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Therefore,

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$:\implies\sf Volume_{\;(mortar)} = \dfrac{1}{12} \times 18$

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$:\implies\sf Volume_{\;(mortar)} = \dfrac{1}{ \cancel{12}} \times \cancel{18}$

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$:\implies\bf Volume_{\;(mortar)} = 1.5\;m^3$

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So,

Volume of wall containing bricks,

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$\star$ Volume of wall = Volume of wall - Volume of mortar

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$:\implies\sf Volume_{\;(wall)} = 18 - 1.5$

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$:\implies\bf Volume_{\;(wall)} = 16.5\;m^3$

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$\bf Dimensions_{\;(brick)} = \begin{cases} & \text{Length = 22 cm = 0.22 m } \\ & \text{Breadth = 12.5 cm = 0.125 m} \\ & \text{Height = 7.5 cm = 0.075 m} \end{cases}$

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Bricks are also in cuboidal shape.

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So, As we know that,

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$\star{\boxed{\sf{\purple{Volume\;of\;cuboid = l \times b \times h}}}}$

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Volume of one brick,

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$\;\;\;\;\;\;\;\small\sf \underline{Putting\;values\;:}$

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$:\implies\sf Volume_{\;(brick)} = 0.22 \times 12.5 \times 0.125$

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$:\implies\bf Volume_{\;(brick)} = 0.0020625\;m^3$

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Therefore,

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$\sf\star\; No.\;of\;bricks = \dfrac{Volume\;of\; bricks}{Volume\;of\;one\;brick}$

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$:\implies\sf No.\;of\;bricks = \dfrac{16.5}{0.0020625}$

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$:\implies{\underline{\boxed{\sf{\pink{No.\;of\;bricks = 8000}}}}}\;\bigstar$

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$\therefore$ Hence, Number of bricks in the wall are 8000.