Question

15. Minimum de Broglie wavelength is associated with (Assume all are moving with same velocity)
(1) Electron
(2) Proton
(3) CO, molecule
(4) SO, molecule​

Answer 1

Answer:

Among the given particles, Proton will have the minimum de Broglie wavelength.

Explanation:

• This is because de Broglie’s wavelength depends upon the mass and velocity of a particle, and assuming the velocity of all the particles are same, the mass of the particle will determine its wavelength.
• De Broglie’s wavelength $\lambda=\frac{h}{m v}$  where h is the Planck’s constant, m is the mass and v is the velocity of the particle.
• The molecular mass of SO is greater than that of CO and hence it will have the minimum de Broglie’s wavelength.
• The electron has smallest mass and hence will have maximum wavelength followed by proton and CO.

Answer 2

Answer:

Among the given particles, Proton will have the minimum de Broglie wavelength.

Explanation:

This is because de Broglie’s wavelength depends upon the mass and velocity of a particle, and assuming the velocity of all the particles are same, the mass of the particle will determine its wavelength.

De Broglie’s wavelength \lambda=\frac{h}{m v}λ=

mv

h

where h is the Planck’s constant, m is the mass and v is the velocity of the particle.

The molecular mass of SO is greater than that of CO and hence it will have the minimum de Broglie’s wavelength.

The electron has smallest mass and hence will have maximum wavelength followed by proton and CO.