Question

15 mL of a 0.16 M solution of glucose was diluted until the total volume reached 95 mL. What is the concentration of new solution? *

Answer 1

Answer:

Using M1V1 + M2V2 = MfVf ( f = final)

So,

15 X 0.16 + 0 X (95-15) = M X 95

So, Mf = 0.025