Question

15. MNOPQR is a hexagon of side 6 cm each. Find the area of the given hexagon in two different methods.

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Answer 1

Answer:

$\huge\colorbox{pink}{Question}$

MNOPQR is a hexagon of side 6 cm each. Find the area of the given hexagon in two different methods.

TO FIND :

The area of the hexagon.

SOLUTION :

Side of the hexagon (a) - 6cm.

Area of hexagon = 3 Underoot

$3 × \frac{a²}{2}$

= 3underoot

$3 × \frac{6}{2}$

= 93.53 Cm

FINAL ANSWER :

93.53 CM.

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Answer 2

Answer:

$\huge \mathbb \red{\underline{QU€STION:}}$

MNOPQR is a hexagon of side 6 cm each. Find the area of the given hexagon in two different methods.

ANSW€R:

Area of traepezium NOPQ

in traepezium NOPQ

OP & NQ are parallel sides

Height is OA

Here,

OP = 5 cm

NQ = 11cm

and height = OA = OM/2 = 8/2 = 4cm

Area of traepezium NOPQ = ½ × sum of parallel sides × height = ½ × (OP + NQ) × OA

= ½ × (5 + 11) × 4

= ½ × 16 ×4

= 8 × 4

= 32cm

Area of hexagon MNOPQ = 2 × area of traepezium BCDF

= 2 × 32

= 64cm

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