Question

15 moles of H2 and 5.2 moles of I2 are mixed and allowed to attain equilibrium at 500oC.at equilibrium at, the concentration of HI is found to be 10 moles.The equilibrium constant for the formation of HI is

Answer 1

Let the degree of dissociation be = x
H2                 I2                     2HI
15-x             5.2-x                   2x
Given:concentration of HI is 10 moles
therefore, 2x=10, x=5
H2 = 15-5= 10
I2 = 5.2-5= 0.2
K=10*10/10*0.2 = 50

Answer 2

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