Question

15.Name the product formed when, Lead hydroxide reacts with
excess of Sodium hydroxide​

Answer 1

When sodium hydroxide $NaOH$ is added to a solution containing lead ions, lead hydroxide precipitates. $Pb(OH)_{2}$ precipitates out of solution as a white solid that is soluble in excess $NaOH$ to produce a colourless solution. The addition of sodium hydroxide to a solution is employed as a test for positive metal ions.

$\mathrm{Pb}(\mathrm{OH})_{2}+2 \mathrm{NaOH}_{\text {(excess) }} \rightarrow 2 \mathrm{H}_{2} \mathrm{O}+\mathrm{Na}_{2} \mathrm{PbO}_{2}$

disodium lead dioxide is a product formed when Lead hydroxide reacts with an excess of Sodium hydroxide.

Answer 2

The product formed when lead hydroxide reacts with an excess of sodium hydroxide is colourless sodium plumbite.

Explanation:

 $Pb{\left(oh\right)}_2+2NaOH(excess)\rightarrow2H_2O+Na_2PbO_2(aq)$

• when lead hydroxide reacts with sodium hydroxide it gives the precipitate of white lead.
• sodium hydroxide is an alkali that absorbs vapour of water and carbon dioxide from the air.
• lead hydroxide was also obtained from adding the sodium hydroxide to lead nitrate which is a colourless inorganic compound. excess addition of sodium hydroxide to lead hydroxide gives sodium plumbite
• sodium plumbite is an irritating and hazardous substance that is toxic and corrosive in nature.