Question

15 points
| 2. An elevator descends into a mine shabt at the:
rate of 6 meters per minute. If the descent.
starts from 10m above the ground level, low:
long will it take to reach -350​

Answer 1

Answer:

1 hour.

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Answer 2

Given:

An elevator descends into a mine shaft at the rate of 6m/min.

Now, the total distance mine shaft have to travel = -350 - 10 = - 360 m[Negative sign represents it goes down]

So, total time taken = 360/6 = 60 minutes  (or) 1 hour.

Hope it help!