Question

15 points and will be marked brainliest!

What is the perimeter of the rectangle?
Length of 4√8
Width of 5√12 + 6√20


A.) 8√2+ 10√3 + 12√5

B.) 4√2 + 5√3 + 6√5

C.) 16√2+ 20√6 + 24√10

D.) 16√2 + 20√3 + 24√5

Please explain answer

Answer 1

$\bold{\underline{\red{\mathcal{\huge{\star\:\:Hey \:\:mate\:\:\star}}}}}$

$<b>Solution:$

Length of rectangle = 4√8

Width of rectangle = 5√12 + 6√20

Perimeter of rectangle = 2( l + w )


=> 2( 4√8 + 5√12 + 6√20)


$\bold{ = >2( 4 \sqrt{2 \times 2 \times 2} + 5 \sqrt{2 \times 2 \times 3}} \\ \bold{ + 6 \sqrt{2 \times 2 \times 5} }) \\ \\ \bold{= >2(8 \sqrt{2} + 10 \sqrt{3} + 12 \sqrt{5}) } \\ \\ = > \bold{16 \sqrt{2} + 20 \sqrt{3} + 24 \sqrt{5} }$

Hence, Option [D] is right.

$\pink{\bold{\boxed{\boxed{16 \sqrt{2} + 20 \sqrt{3} + 24 \sqrt{5}}}}}$

Thanks for the question!

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