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class 9 physics question
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according to the universal law of gravitation , the force exerted on an object by mass m is given by.
f=gMm/r^
where mass of earth M= 6*10^24kg
mass of object m= 1 kg
universal gravitational constant=6.7*10^-11nm^kg^
since the object on the surface of the earth
radius = 6.4*10^6
f=gMm/r^
f=6.7*10^-11*6*10^24*1/(6.4*10^6)^
f=9.8 N( newton becoz there is mass and force )
plzzzzzz mark it brainloest if it is useful
pls
f=gMm/r^
where mass of earth M= 6*10^24kg
mass of object m= 1 kg
universal gravitational constant=6.7*10^-11nm^kg^
since the object on the surface of the earth
radius = 6.4*10^6
f=gMm/r^
f=6.7*10^-11*6*10^24*1/(6.4*10^6)^
f=9.8 N( newton becoz there is mass and force )
plzzzzzz mark it brainloest if it is useful
pls
ashish164:
we will divide both
yup
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