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● A Bike Accelerated uniformly from rest to a speed of 7.10 m/s over a Distance of 35.4 m . Determine The acceleration of the Bike
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Answer:
Given -
u = 7.10m/s
v =0m/s
s = 35.4m
a =?
v^2 = u^2 + 2as
0^2 =7.10^2 + 2 × a × 35.4
0 = 50.41 + 70.8 × a
-50.41 = 70.8 × a
a= -50.41/70.8
a = 0.71 m/s^2
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