Math, asked by creamiepie, 9 months ago

15 points

Solve the equation

cos 3x = sin 2x ​

Answers

Answered by shikha1405
1

cos 3x = sin 2x

sin (90-3x) = sin 2x

90 – 3x = 2x

90= 2x + 3x

90 = 5x

x = 90/5

x = 18

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Answered by Anonymous
22

Step-by-step explanation:

ANSWER

 \cos3x  =  \sin2x  \sin(90 - 3x)  =  \sin2x \\  \\ 90 - 3x = 2x \\  \\  = 90 = 3x + 2x \\  \\  = 90 = 5x \\  \\  \frac{90}{5} = x \\  \\ x = 18

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