Question

15 question both parts in full explanation​

Answer 1

(i) AB // CD {given}

∠ EGB = 55° {given}

∠EGB = ∠GHD = 55° -> corresponding angles

∠ GHD= ∠ PHQ = 55° -> vertically opposite angles

∠ OPH + ∠PHQ + ∠PQH = 180° -> angle sum property of a triangle

90°+55°+ ∠ PQH = 180°

∠PQH = 180°- 145°

∠PQH = 35°