Question

15. Romar is twice as old as Mavic. Jaypee is 8 years older than Romar. Write an algebraic
equation showing that twice the sum of Romar and Mavic ages will result to Jaypee's age.​

Answer 1

Answer:

Answer:

Age Problem

Romar's age = 2q

Jaypee's age = 2q + 2

Sum of Romar and Mavic's ages = 2q + q = 3q

Step-by-step explanation:

Given that Romar is twice as old as Mavic and Mavic is q years old then, Romar's age will be 2q.

Given that Jaypee is 2 years older than Romar then Jaypee's age will be 2q + 2.

If Romar's age is 2q and Mavic's age is q then the sum of their ages will be 2q + q which is equals to 3q.

Answer 2

Given : Romar is twice as old as Mavic.

Jaypee is 8 years older than Romar.

To Find :  Write an algebraic equation showing that twice the sum of Romar and Mavic ages will result to Jaypee's age.​

Solution:

Let say Mavic. age = M

Romar age  = 2M

Jaypee is 8 years older than Romar.  =  2M +  8

twice the sum of Romar and Mavic ages will result to Jaypee's age.​

2 ( 2M + M)   =  2M + 8

is the required algebraic equation

=> 6M  = 2M + 8

=> 4M = 8

=> M = 2

Mavic. age = 2

Romar age  = 4

Jaypee  age = 12

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