15. Show that incident ray CA || DB
reflected ray if two mirrors are kept
perpendicularly as shown in the give
figure.
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Answer:
angle BOA=90°(given)
anglePBO=90°(normal ray is always perpendicular)
anglePAO=90°
since we know that in a quadrilateral sum of all angles is 360°
hence angleBPA=90°
Now in triangle PBA
angle2 + angle3 = 90° —(1)
now by laws of reflection
angle1=angle2—(2)
and,angle3 = angle 4—(3)
from 1,2 and 3
angle 1 + angle 4 =90°—(4)
on adding 1 and 4 we get
angle 1 +angle2+angle3+angle4=180°
so angleBAC + angle ABD = 180°
hence CA is parallel to DB since sum of cointerior angles is 180°.
prooved
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