Question

15. .
sin 30° sec 60° + cos 30° cosec 60°
sec 45° cot 45° cosec 45°
WW2
2.
1211
(3) 13​

Answer 1

Answer:

Step-by-step explanation:

sin30°sec60° + cos30°cosec60°

sec45° cot45° cosec45°

sin30° = 1/2

sec60° = $\frac{1}{cos60^{o}}$ = 2

cos30° = $\frac{\sqrt{3}}{2}$

cosec60° = $\frac{1}{sin60^{o} }$ = $\frac{2}{\sqrt{3}}$

sin30°sec60° + cos30°cosec60° = 1/2 × 2 + (√3/2) × (2/√3) = 1 + 1 = 2

sec45° cot45° cosec45° = √2 × 1 × √2 = 2

sin 30° sec 60° + cos 30° cosec 60° = sec 45° cot 45° cosec 45°