Question

15. Sohan borrowed Rs4000 in compound interest at the rate of 15%p.a. for three years. Let us find the amount he has to pay back at the end of three years and also the compound interest
to be paid.

Answer 1

Answer:

Amount = Rs 6083.50

CI = Rs 2083.50

Step-by-step explanation:

$\bold{Given}$

principal = Ra4000

Rate of Interest = 15%

Time = 3yrs.

We Know The Formula :

$\red{A = p \bigg(1 + \frac{r}{100} \bigg)}^{t}$

A = Amount

p = Principle

r = Rate of Interest

t = time

$A = 4000 \bigg( \frac{115}{100} \bigg)^{3}$

$A = 4000 \times \frac{115}{100} \times \frac{115}{100} \times \frac{115}{100}$

$A = 4 \cancel{000 }\times \frac{23}{ 2\cancel{0}} \times \frac{23}{ 2\cancel{0}} \times \frac{23}{ 2\cancel{0} }$

$A = \cancel4 \times \frac{23 \times 23 \times 23}{ \cancel{2} \times \cancel2 \times 2}$

$A = \frac{12167}{2}$

$\tt{A = rs \: 6083.50 \: }$

$\pink{CI = amount - principal}$

$CI = 6083.50 - 4000$

$\tt \: CI = rs \: 2083.50$