Question

15. Solve the following pair of linear equation by elimination method
2(ax-by)+(a+4b)=0 and 2(bx+ay)+(b-4a)=0​

Answer 1

Step-by-step explanation:

2(ax+by)+(a+4b)=0

2ax+2by+a+4b=0           Equation 1

2(bx+ay)+(b-4a)=0

2bx+2ay+b-4a=0           Equation 2

Multiplying 1 by b:

2abx+2b^2y+ab+4b^2=0   Equation 3

Multiplying 2 by a:

2abx+2a^2y+ab-4a^2=0   Equation 4

Subtracting 4 from 3:

2abx+2a^2y+ab-4a^2-2abx-2b^2y-ab-4b^2

2a^2y-4a^2-4b^2-2b^2y=0

Solve and find the value of y. Then substitute to find x.