15. Solve the following systems of equation and find the value of x / y :
23x + 29y = 98 ;
29x + 23y = 110
Standard:- 10
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Answers
Answered by
1
Adding both equations
52x+52y=208
x+y=208÷52
x+y=4..........eqn 1
Subtracting both equations
6x-6y=12
x-y=2.........eqn 2
ADDING EQUATUON 1 AND 2
2x=6
x=3
PUTTING VALUE OF X IN EQUATION 1
x+y=4
y=4-3
y=1
ANSWER...X=3,Y=1.
HOPE THIS ANSWER HELPS YOU
52x+52y=208
x+y=208÷52
x+y=4..........eqn 1
Subtracting both equations
6x-6y=12
x-y=2.........eqn 2
ADDING EQUATUON 1 AND 2
2x=6
x=3
PUTTING VALUE OF X IN EQUATION 1
x+y=4
y=4-3
y=1
ANSWER...X=3,Y=1.
HOPE THIS ANSWER HELPS YOU
Answered by
5
Given 23x + 29y = 98 ------- (1)
Given 29x + 23y = 110 ------ (2)
On adding (1) & (2), we get
= > 23x + 29y + 29x + 23y = 98 + 110
= > 52x + 52y = 208
= > x + y = 4 ------- (3)
On subtracting (1) & (2), we get
= > 29x + 23y - 23x - 29y = 12
= > 6x - 6y = 12
= > x - y = 2 --------------- (4)
On solving (3) & (4), we get
= > x + y = 4
= > x - y = 2
----------------
2x = 6
x = 3.
Substitute x = 3 in (3), we get
= > x + y = 4
= > 3 + y = 4
= > y = 4 - 3
= > y = 1.
Therefore the value of (x/y) = (3/1)
= 3.
Hope this helps!
Given 29x + 23y = 110 ------ (2)
On adding (1) & (2), we get
= > 23x + 29y + 29x + 23y = 98 + 110
= > 52x + 52y = 208
= > x + y = 4 ------- (3)
On subtracting (1) & (2), we get
= > 29x + 23y - 23x - 29y = 12
= > 6x - 6y = 12
= > x - y = 2 --------------- (4)
On solving (3) & (4), we get
= > x + y = 4
= > x - y = 2
----------------
2x = 6
x = 3.
Substitute x = 3 in (3), we get
= > x + y = 4
= > 3 + y = 4
= > y = 4 - 3
= > y = 1.
Therefore the value of (x/y) = (3/1)
= 3.
Hope this helps!
siddhartharao77:
:-)
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