Question

15 tan ^2A + 4sec^A = 23 then tan ^A =

Answer 1

the answer will be as...

Answer 2

15tan^2 x +4(tan^2 x+1)=23

= 19tan^2 x +4 = 23

= 19tan^2 x = 19

= tan^2 x =1

= tanx= 1

therefore

secx=root2

cosecx=root2

sinx=1/root2

(secx+cosecx)^2-sin^2 x =(2root2)^2-1/2=8-1/2=15/2

I AM SOLVING A AS X