15 terms an arithmetic sequence 25and
25 terms of the 15
Write sequence
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Answer:
The 25th term of the sequence that begins with 3 is 147.
Step-by-step explanation:
The given sequence is 3, 9, 15, 21, 27, …
It is an arithmetic progression so the common difference between all consecutive numbers is 6.
Let a1 be the first term of the sequence and d be a common difference.
Therefore, a1 = 3 and d = 6.
For nth term, the nth term of the AP formula is an = a1 + (n - 1) d
⇒ a25 = 3 + (25 - 1) 6
= 3 + 24 × 6
= 3 + 144
= 147
Thus, the 50th term of the sequence is 147.
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