Math, asked by KDboss, 1 year ago

15. The age of Supriya and Neetu are in the ratio 5:6. After two years, their age will be in the ratio
6:7. What are their present ages?​

Answers

Answered by Anonymous
27

• Let present age of Supriya be 5M and present age of Neetu be 6M.

» After two years.

Age of Supriya = 5M + 2

And age of Neetu = 6M + 2

• And the ratio of their ages is 6:7.

A.T.Q.

=> \dfrac{5M\:+\:2}{6M\:+\:2} = \dfrac{6}{7}

Cross-multiply them

=> 7(5M + 2) = 6(6M + 2)

=> 35M + 14 = 36M + 12

=> 35M - 36M = 12 - 14

=> -M = - 2

=> M = 2

_______________________________

Present age of Supriya = 5M = 5 × 2 = 10 years.

Present age of Neetu = 6M = 6 × 2 = 12 years

____________ [ANSWER]

\dfrac{5M\:+\:2}{6M\:+\:2} = \dfrac{6}{7}

Put value of M in above equation.

=> \dfrac{5(2)\:+\:2}{6(2)\:+\:2} = \dfrac{6}{7}

=> \dfrac{10\:+\:2}{12\:+\:2} = \dfrac{6}{7}

=> \dfrac{12}{14} = \dfrac{6}{7}

=> \dfrac{6}{7} = \dfrac{6}{7}

___________ [HENCE VERIFIED]

Answered by soni4357
3

Answer:

x = 2

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