Question

15. The ages of A and B are in the ratio 8:3. Six years hence, their ages will be in the ratio 9:4.
Find their present ages.
in the alloy is​

Answer 1

correct question :

The ages of A and B are in the ratio 8:3. Six years hence, their ages will be in the ratio 9:4.

Find their present ages.

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Given:

The ages of A and B are in the ratio 8:3.

Need to find :

what's their present ages.

❑Let the present age of A and present age of B is 8x & 3x

According to the question

• six years hence , their ages will be in the ratio 9:4

Therefore,

⇒8x + 6 /3x + 6 = 9/4

⇒4( 8x + 6 ) = 9 ( 3x + 6 )

⇒ 32x + 24 = 27x + 24

⇒32x - 27 x = 54 - 24

⇒5x = 30

⇒x = 30/5

➨x = 6

❑ Hence, their present are are:

• A's present age , 8x = 8 (6) = 48 years

• B's present age, 3x = 3 (6) = 18 years

Answer 2

Answer:

Let the coefficient be x.

A's age = 8x

B's age = 3x

Six years hence,

Ages will be 8x+6 and 3x+6.

Now, As per the question,

(8x+6) /(3x+6) = 9/4

32x+24 = 27x+54

5x = 30

x = 6.

Present ages of A and B will be 48 and 18 years.