Question

15. The area of a rectangular field is 456m2 and its length is 24m find the breadth and
perimeter of the field.
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Answer 1

Answer:

$\blue{area \: of \: rectangle = l \times b}$

$\pink{l \times b = 456 {cm}^{2}}$

$\green{24m \times b = 456 {m}^{2} }$

$\red{b = \frac{456}{24}cm }$

$\orange{b = 19cm}$

Therefore the breadth is 19cm.

$\blue{perimeter \: of \: rectangle = 2(l + b)}$

$\green{2(24cm + 19cm)}$

$\orange{2 \times 43cm}$

$\red{permeter \: of \: rectangle = 86}$

Hope it helps you ☺

Answer 2

Answer:

$\huge\pink{\boxed{\green {\mathbb{\overbrace {\underbrace{\fcolorbox{red}{red}{\underline{\pink{†Solution†}}}}}}}}}$

Let us assume length be 'l' and breadth be 'b'

GIVEN:

$area \: of \: rectangle = 456 {m}^{2}$

$lenght = 24m$

We have to find:

Breadth and perimeter of this rectangular field.

Now:

Area of rectangle= (l×b)=456m²

=>(24×b)m=456m² (Length=24m)

=>b=456m²/24m

=>b=19m

So we have breadth (b)=19m and we have given 24m as length (l)

As we known perimeter of rectangle= 2×[l+b]

Therefore perimeter of this rectangular field:

=2×[l+b]

=2×[24+19]m

=(2×43)m

=86m

Hence the breadth and perimeter are 19m and 86m respectively.