Question

15. The chloride of a metal 'M' contains 47-23% of the metal. 1 g of this metal displaced
from a compound 0-88 g of another metal 'N'. Find the equivalent weight of 'M'
and 'N' respectively
(31.77 ; 27.96)
​

Answer 1

Answer:

39.10

Explanation:

The chloride of a metal 'M' contains =  47-23% of the metal. (Given)

Metal displaced = 1g

Thus, in 100g of Chloride 47.23g is the metal and the chlorine will be -

= 100 - 47.23

= 52.77g of Chlorine

Equivalent weight of Chlorine = Atomic weight/valency

= 35/1

= 35

Equivalent weight of metal = Mass of metal/ Mass of oxygen × 35

= 52.77/ 47.23 × 35

= 39.10

Thus, the equivalent weight of 'M' will be 39.10g.