Physics, asked by rathod99, 1 year ago

15. The distance travelled by a particle starting from rest
n
a
and moving with an acceleration 4/3ms in the third
second is
[AIPMT (Prelims)-2008]
(1) 19/3m
(2) 6 m

(3) 4 m
(4)10/3m​

Answers

Answered by Rajputsaurabhsingh
18

Hey dude here is your Answer------------------------ ✔️❣️✔️ ❣️✔️ ❣️✔️ ❣️✔️ ❣️

Given , initial velocity = 0

Acceleration. = 4/3ms-¹

Time. = 3 sec

Distance = ut+ 1/2 at²

Distance = 0×3 + 1/2 ×4/3 ×3²

= 2/3× 9

= 6 m ...

*The correct answer is 6m .......

✔️✔️✌️Hope it helps you✔️✔️✌️

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