Question

15. The floor of a room is in the shape of a square of side 4.8 m. The floor is to be
covered with square tiles of perimeter 1.2 m. Find the cost of covering the floor if
each tile costs 27.
ning the plot at the rate of​

Answer 1

Answer:

Step-by-step explanation:

Area of squre floor is =side *side

=4.8*4.8

=23.04 m^2

Given, perimeter of an squre tiles=1.2 m

Perimeter of squre = 4*side

4*side=1.2

Side=1.2/4

=0.3m

Area of the squre tiles = side*side

=0.3*0.3

=0.09m^2

Required tiles for the squre floor=23.04/0.09=256

Cost of 1 tiles is rs=27

Then cost of 256 tiles = 256*27= Rs.6912

Answer 2

area or room =side×side

=4.8×4.8=23.04

side of tiles =perimeter /4 = 1.2/4 =0.3

area of tiles 0.3×0.3=0.9

required tiles=area of room/ area of tiles

=23.04/0.9=256

then coast of 1tiles =2.

therefore 256 tiles = 256×27

=6912