Question

15. The length of a rectangle is 1 m greater than its width. If the length is increased by 2 m and the width is decreased by 6 m, the area decreases by 50 m2. What are the dimensions of the rectangle?​

Answer 1

Answer:

All step are clearly written and explained in given solution.

Answer 2

Answer:

Let the width of rectangle be x meter

then, length = x + 1 meter

Area of rectangle = l × b

=> x ( x + 1 )

=> ( x² + x ) m² ( . . . 1 )

If the length increased by 2 m

= x + 1 + 2 = x + 3 m

and width decreased by 6 m = x - 6 m

Now, area of rectangle

=> ( x + 3 ) ( x - 6 )

=> x² - 6x + 3x - 18

=> ( x² - 3x - 18 ) m² ( . . . 2 )

previous area ( 1 ) is decrease by 50 m² by this area ( 2 )

x² + x - 50 = x² - 3x - 18

x² - x² + x + 3x = -18 + 50

4x = 32

x = 32 / 4

x = 8

hence, width = x = 8 m

length = x + 1 = 8 + 1 = 9 m

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