Question

15. The length of a side of a square field is 4 m. What will be the altitude of the rhombus, if
the area of the rhombus is equal to the square field and one of its diagonal is 2 m?

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Answer 1

Answer:

attitude of the rhombus = (16/√16)m

Step-by-step explanation:

area of the square field = (4 * 4)sq m.

area of rhombus= 16 sq m.

On diagonal of the rhombus = 2m

let the other diagonal of the rhombus X metre.

Area of rhombus = {(x*2)/2}sq m = x sq m

so x = 16.

therefore , diagonal of the rhombus are of 2 M and 16 M and they are perpendicular bisector of one another.

each side of the rhombus = √{(1^2)+(8^2)} m = √65m

hence Attitude of the rhombus = (16/√65) metre.

this is your answer friends

.......... Salmønpanna