Question

15. The meter taxi opens out with reading of Rs. 5 and then runs up by Rs. 9 1 point for each km travelled. How much should be paid for the taxi after travelling 10 kms? O a) Rs. 90 Ob) Rs. 80 O c) Rs. 95 O d) Rs. 100​

Answer 1

Answer:

The taxi fare for first km=15

The taxi fare for 2nd km=15+8=23

The taxi fare for 3rd km=15+8+8=31 and so on,

Therefore, the taxi fare form the sequence 15,23,31,...

Clearly, it is an AP with first term a=15and common difference d=8

Therefore, answer is 0.

Answer 2

Step-by-step explanation:

Given :-

The meter taxi opens out with reading of Rs. 5 and then runs up by Rs. 9 1 point for each km travelled.

To find:-

How much should be paid for the taxi after travelling 10 kms?

Solution:-

Open reading of a taxi = Rs. 5

The fixed charge of a taxi = Rs. 5

The charge for running km each = Rs. 9

The charge for 1st km = 5+9 = 14

Then the charges are

14

14+9 = 23

23+9 = 32

32+9 = 41

This is the application of Arithmetic Progression

We have,

First term (a) = 14

Common difference (d) = 9

We know that

nth term of an AP = an = a+(n-1)d

Total charge for 10kms.

=>a10 = a+(10-1)d

=> a10 = a+9d

=> a10 = 14+9(9)

=> a10 = 14+81

=> a10 = 95

Answer:-

The amount should be paid for the taxi after travelling 10 kms is Rs. 95

Used formulae:-

• nth term of an AP = an = a+(n-1)d
• a = First term
• d = Common difference
• n = number of terms