Question

15.The path difference between the two waves y1=a1sin(wt-2piex/lamda) and y2=a2cos(wt-2piex/lamda +theeta) is

Answer 1

Hey dear,

● Answer -
∆x = λ(θ+π/2)/2π

● Explanation -
Given wave eqns are,
y1 = a1sin(ωt-2πx/λ) ...(1)
y2 = a2cos(ωt-2πx/λ+θ)
y2 = a2sin(ωt-2πx/λ+θ+π/2) ...(2)

Comparing (1) & (2), phase difference is
∆θ = θ+π/2

Path difference is given by -
∆x = ∆θ × λ / 2π
∆x = λ(θ+π/2)/2π

Hence, path difference is λ(θ+π/2)/2π .

Thanks for asking...

Answer 2

Explanation:

Please see the picture

I hope it helps you ...