Math, asked by hanumapeddaiah, 14 hours ago

15. The perimeter of a rectangle is 16x³ - 6x² + 12x + 4. If one of its sides is 8x² + 3x, find the other side.

Answers

Answered by shibanmandi0
1

Answer:

The other side is 8x³ - 11x² + 3x + 2.

Step-by-step explanation:

As know perimeter of a rectangle is

2( l + b )

So we can write that

2( l + b ) = 16x³ - 6x² + 12x + 4

2l + 2b = 16x³ - 6x² + 12x + 4

or, 2l + 2(8x² + 3x) = 16x³ - 6x² + 12x + 4

or, 2l + 16x² + 6x = 16x³ - 6x² + 12x + 4

or, 2l = 16x³ - 16x² - 6x² + 12x - 6x + 4

or, 2l = 16x³ - 22x² + 6x + 4

or, 2l = 2(8x³ - 11x² + 3x + 2)

or, l = 2(8x³ - 11x² + 3x + 2)/2

or, l = 8x³ - 11x² + 3x + 2

Therefore, the other side is 8x³ - 11x² + 3x + 2.

Answered by arasanjayray1980
0

Answer:

b=16x^3-22x^2+6x+4

I hope I help your

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