Question

15. The perimeter of a rhombus is 20 cm and length of
one diagonal is 8 cm. Then length of other diagonal
is​

Answer 1

$answer$

In a rhombus all sides are equal so ,

Perimeter=4s(=20cm,given)

s=5cm.

So, it is known that diagonals intersect normal(perpendicular) to each other and bisect each other. So, one of the diagonals is 8cm and let’s say other diagonal is xcm in measure. Then, (8/2)^2 +(x/2)²=5²

4^2 +( x²)/4 = 5^2

16+(x²)/4=25

(x²)/4=9

x²=36

x=+6 cm(Length can not be negative so not -6)

Second diagonal length=6cm