Question

15. The perimeter of a square and rectangle are each equal to 48 m and difference between area is 4 m2. The breadth of the rectangle is​

Answer 1

Perimeter of square P_s = 4a

4a = 48

a = 12

Perimeter of Rectangle, P_r = 2(l+b)

2(l+b) = 48

l + b = 24

Area of square, A_s = a^2 = 12^2 = 144

Area of Rectangle, A_r = l*b

A_s - A_r = 4

A_r = A_s - 4

l*b = 140

l = 140/b

Now,

l + b = 24

$\frac{140}{b} + b = 24 \\ \\ 140 + {b}^{2} = 24b \\ {b}^{2} - 24b + 140 = 0 \\ {b}^{2} - 14b - 10b + 140 = 0 \\ b(b - 14) - 10(b - 14) = 0 \\ (b - 10)(b - 14) = 0 \\ \\ b = 14 \: and \: 10$

Breadth of Rectangle, 14 and 10

Answer 2

Answer:

10 m

Step-by-step explanation:

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