Question

15. The present age of son is half the age of his father. Fifteen years ago, the father was thrice as old as his
son. What are their present ages?​

Answer 1

Answer:

Given that,

The present age of son is half the present age of his father.

Let the present age of the father be 2x.

Therefore present age of the son = 2x/2 = x years

ATQ,

10 years ago, father's age was thrice as old as his son.

➡ 3(x - 10) = 2x - 10

➡ 3x - 30 = 2x - 10

➡ 3x - 2x = -10 + 30

➡ x = 20

Hence their present ages are :-

Father's present age = 2x = 40 years

His son's present age = x = 20 years

Step-by-step explanation:

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Answer 2

Answer:

Let the present son age will be = x

Let the present father age will be = 2x

15 year ago their age will be

father age = 3(2x-15)

son age. = x-15

Step-by-step explanation:

6x-45= x-15

6x-x=45-15

5x = 30

x = 30 /5

x =6

son present age = x = 6

Father present age = 2x = 2×6= 12