Question

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15. The pressure of a liquid of density 1g/cm at a depth 2 cm from the surface of liquid
is (atmospheric pressure = 1 x 105 Pa and g = 10 m/s2).
11.002 x 105 pa 2) 1.004 * 105 pa 3) 1.002 x 104 pa 4)1.02 x 10Spa​

Answer 1

Answer:

Explanation:

so pressure = height*density*acceleration due to gravity

so 2*1*10(is absolutely wrong) because all units are not the same

so 1g/cm^3 = 1000g/cm^3

so 1000*0.02*10=200PASCALS OR 0.002*10^5 PASCALS

this is only due to liquids height and some pressure is acting due to atmosphere that is 1*10^5 pascals

so net pressure =1*10^5 pascals + 0.002*10^5pascals = 1.002*10^5Pascals