Math, asked by paridabuddhadev1, 4 months ago

15. The product of two numbers is
123904 and double of one of them
is 1408: What is the other? How
many times in succession must 201
be added to 3166 to make the final
sum 10000?​

Answers

Answered by sajalsultania
1

Answer:

176 and 34 is correct answer

Answered by MathisMath
0

Answer:

ans1) 176

ans2) 34

Step-by-step explanation:

Let the 2 numbers be x and y

Given product = 123904 which is

xy = 123904 __________(1)

also double of a number is 1408

2x= 1408

x=1408/2

x=704

put this value in (1)

704y= 123904

y = 123904/704

y= 176

_____________________________________

According to question ,

201x + 3166 = 10000

201x = 10000- 3166

201x= 6834

x= 6834/201

x= 34

Pls mark this as brainliest answer

Similar questions