Question

15. The sides of a triangle are 21 cm, 17 cm, and 10 cm. Calculate its area and length of the height
on the longest side.
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Answer 1

answer:

a=21,b=17,c=10

now semi perimeter =a+b+c/2

after doing it

do root of s(s-a)(s-b)(s-c)

if you do it you can get area in any cases

Answer 2

answer -

$84 {cm}^{2}$

Step-by-step explanation:

: - according to the herons formula

given -

a- 21 cm

b- 17 cm

c- 10 cm

semi perimeter = 1/2 of perimeter

=( 21+17+10)2

= 48 /2

= 24

semi perimeter is also called 's'

so , Area of triangle = √ s ( s-a ) ( s-b ) (s-c)

so , = √ 24 ( 24 - 21 ) ( 24 - 17 ) ( 24 - 10 )

= √ 24 × 3 × 7 × 14

= 7 × 3 × 2 ×2

= 84

so , area of ∆ is 84 cm^2

so the length of height in the side is 10 cm

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