Question

15. The sum of 3 consecutive multiples of 4 is 252. Find the multiples​

Answer 1

Let the multiples be 4x,4x+4,4x+8

APQ

4x+4x+4+4x+8=252

12x+12=252

12(x+1)=252

x+1=252/12= 21

Therefore,

x=20

The multiples are-

i) 4 x 20 = 80

ii) 4 x 20 +4 = 84

iii) 4 x 20 +8 = 88

Hope you will understand.....Thank You...