Question

15. The sum of all the possible remainders, which can be obtained when the cube of a natural number is divided by 9, is [NTSE/Stage-11/2016) (A) 5 (B) 6 (C) 8 (D) 9​

Answer 1

Answer:

D) 9

Step-by-step explanation:

Cube of a natural number is of the form 9m,9m+1,9m+89m,9m+1,9m+8

So possible remainder are 0,1,80,1,8

Sum=0+1+8=9