Question

15. The sum of squares of the first ‘n' natural numbers is given by n(n+1)(2n+1) Find the sum 6 of squares of the first 12 natural numbers.

Simplify 3a – 26 - ab -(a-b+ ab) + 3ab + b-a.​

Answer 1

Answer:

Put n=10 in the given expression

Sum of squares of first n natural numbers is given by

6

1

n(n+1)(2n+1)

Therefore, the sum of squares of the first 10 natural numbers

=

6

1

10(10+1)(2×10+1)

=

6

1

×10×11×21

=385