Question

15.
The sum of the digits of a two digit number is 10. The number obtained by
interchanging the digits exceeds the original number by 36. Find the original
O
number.​

Answer 1

Answer:

Let the unit place be "x"

and ten's place be "y"

Number will be 10y+x

Now,

Number obtained by reversing the digits will be

10x+y

A/Q

10y + x + 36 = 10x + y

9x - 9y = 36

x - y = 4...............eq1

Now, sum of digits is 10 (given)

x + y = 10 ...........eq2

Adding both eq

x + y = 10

+ x - y = 4

2x = 14

x = 7

put the value of "x" in eq2

7 + y = 10

y = 3

Now the number will be 10y + x = 37

Answer 2

Answer:

73

Step-by-step explanation:

let the first number of two digit number be x( tenth place) and other be y respectively.

sum of two digits will be:

x+y=10_____(1)

now, in second step let the original number be 10x+y.

and by interchanging the number we will get,

10y+x.

further, the question says,

10x+y-36 = 10y+x

9x-9y = 36

9(x-y) =36

x-y =4

10-y-y =4

2y =6

y = 3

from equation (1)...

x+3=10

x=7

we know the original number is: 10x+y

so the number is 73.