Question

15.
The sum of the two-digit number and its reverse is m
times the sum of its digits. If the subtraction of the
reverse from the number is n times the subtraction of
the digits, the value of m +n is
(b) 9 (c) 11 (d) 20
(a) 2
​

Answer 1

Hi mate let a two digit number is 24

Then according to above 1st line

24+42 is the m times the sum of the digits

So24+42=66

66=m times the sum of the digits

Sum of the digits=2+4=6

66=m*6

M=66/6

M=11

Same as second case 42-24=n times the subtraction of the digits

So 42-24=18

18=n*4-2

18=n*2

N=9

Now

M+n = 11+9=20 is the correct answer. If you like this keep me. As genius

Answer 2

Answer:

let the two digits of a no. be x+y ... original number will be 10x+y.....inverse of this no. is 10y+x....sum of digits will be x+y and subtraction be x-y....

case one ....10x+y+10y+x=m(x+y)

=> 11(x+y)=m(x+y)

=> m=11

case two. ..... 10y+x-10x-y=n(x-y)

=> 9(x-y)=n(x-y)

n=9

therefore....m+n =9+11=20