Question

15) The total cost of painting the sunshade at the rate of 2 per sq. m is
900 rupees. Find the area of sun shade which is in the form of isosceles
trapezium​

Answer 1

Answer:

450m²

Step-by-step explanation:

Rupees 2 = 1m²

Rs 900 = 900 × 1/2 = 450m²

Answer 2

Answer:

Step-by-step explanation:

Concept:

The concept of geometry and basic division  will be used to solve the question.

Given:

The total cost of painting the sunshade is $Rs. 900/-$ .

The rate of the cost is $Rs.2/-$ per $m^{2}$.

To find:

We need to find the area of the sun shade which have been painted.The shape of the sun shade is isosceles trapezium​

Solution:

The value of total cost is $Rs. 900/-$

The cost per $m^{2}$ is $Rs.2/-$ .

We need to divide the total cost by the rate of the cost of the sun shade.

The area is $\frac{Total \ Cost}{The \ rate \ of \ the \ cost \ per m^{2} } =\frac{900}{2} =450$

Therefore the area of the sun shade which is in the form of isosceles trapezium is $450 m^{2}$ .

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