Question

15. The value of y in the solution of the equation
2^x+y = 2^x- y = ✓8 is​

Answer 1

$\sf { \cancel2}^{(x + y)} = { \cancel2}^{(x - y)} \implies x + y = x - y = \sqrt{8}$

• x + y = √8
• x - y = √8
• x = √8 + y
• then ,
• √8 + y + y = √8
• 2y = √8 - √8 = 0
• y = 0
• Value of y = 0

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Answer 2

Answer:

x = 4, y = 0

Step-by-step explanation:

sub both side by

2x+y=8

- (-) 2x-(+)y=(-)8

= 0 + 2 = 0

= y= 0/2

=. y = 0 _ _ _ (1)

so , 2x +y =8

=. 2x + 0 = 8. _ _ _ _ from (1)

= x = 8/2

= x= 4

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