15) Train A crosses a car moving at 30 kmph in opposite direction in 14.4 seconds. If train A and B can cross a man standing on a platform in 21.6 seconds and 15 seconds respectively and the length of train B is 60 m less than that of train A, then what is the time taken by train A to cross train B running in the same direction?
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Answer:
Solution:
Given:
Speed of the train = 72km/hr
The train passes the platform in 48 sec and the passenger in 30 sec
Concept used:
Speed = distance/time
While a train crossing a man it actually crossing it's own length.
Calculation:
Speed of the train is 72 km/hr = 72 × (5/18) = 20 m/sec
Length of train = speed × time
Length of train = speed × time
⇒ 20 × 30 = 600 m
Now, accordingly
⇒
⇒ x = 960 - 600
⇒ x = 360
∴ The length of the platform is 360 meter
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