Math, asked by rkumar35, 5 hours ago

15) Train A crosses a car moving at 30 kmph in opposite direction in 14.4 seconds. If train A and B can cross a man standing on a platform in 21.6 seconds and 15 seconds respectively and the length of train B is 60 m less than that of train A, then what is the time taken by train A to cross train B running in the same direction?​

Answers

Answered by nilamarts123
1

Answer:

Solution:

Given:

Speed of the train = 72km/hr

The train passes the platform in 48 sec and the passenger in 30 sec

Concept used:

Speed = distance/time

While a train crossing a man it actually crossing it's own length.

Calculation:

Speed of the train is 72 km/hr = 72 × (5/18) = 20 m/sec

Length of train = speed × time

Length of train = speed × time

⇒ 20 × 30 = 600 m

Now, accordingly

⇒ x = 960 - 600

⇒ x = 360

∴ The length of the platform is 360 meter

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