Physics, asked by 1by20ec137, 16 days ago

15 Two impedances (4 + j 10) 12 and (6 + j4) 12 are connected in parallel, across an AC. supply and dissipates 600 W. Calculate the power taken, when the impedances are connected in series across the same supply. (135 36 W​

Answers

Answered by alokdubey884569
0

Answer:

Z = Q/w"C= 100/(21T X 106 X 200 X 10-12) n = 79.6 kn. 6. The impedance-frequency curve for the circuit will have a maximum value of R at ...

Similar questions