Question

15. Two positive numbers x and y are such that
x > y. If the difference of these numbers is 5
and their product is 24, find :
(i) sum of these numbers.
(ii) difference of their cubes.
(iii) sum of their cubes.​

Answer 1

Answer:

Step-by-step explanation:

Given,

x - y = 5

So, x = 5 + y

x * y = 24

Substituting value of x by (5 + y),

(5 + y) * y = 24

So, 5y + y^2 = 24

So, y^2 + 5y - 24 = 0

So, y^2 + 8y -3y -24 = 0

So, y(y + 8) - 3(y + 8) = 0

So, (y + 8)(y - 3) = 0

Now y = 3 as -8 is negative number.

So x = 5 + 3 = 8

So, (i)  x + y = 8 + 3 = 11

     (ii)  x^3 - y^3 = 512 - 27 = 485

    (iii)  x^3 + y^3 = 512 + 27 = 539

Answer 2

here is ur answer

plz look at above pic.

HOPE THIS WILL HELPS U....BE HAPPY......