Math, asked by SoumabhaRana, 8 months ago

15. Two trains of equal length running in opposite directions, pass a student standing
by a side of railway line in 18 secs. and 12 secs, respectively
. In what time will the two
trains cross each other?​

Answers

Answered by eshwaripatil
1

Answer:

Time required to cross each other = 14.4 sec

Step-by-step explanation:

the lengths of the train be X

To cross a person a train has to travel the distance equal to it's own length

So

speed of two trains are = distance/ time taken

X / 18 ......for train say A

X / 12 .........for train say B

To cross them each other they will have to travel a distance equal to sum of their lengths = 2X

and the speed will be equal to the sum of their speeds as they are traveling in opposite direction.

speed = X /18 + X/12

Time required to cross each other

= 2X / ( X /18 + X/ 12)

= 2X / ( 2X/ 36 + 3X / 36)

= 2X ÷ ( 5X/36)

2X × 36

= --------------

5X

2 × 36

= ----------------

5

= 72 ÷ 5

= 14.4 sec

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