15.Two water taps together can fill a tank in 93
8
hours. The tap of larger
diameter takes 10 hours less than the smaller one to fill the tank
separately. Find the time in which each tap can separately fill the tank.
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Answer:
Let the tap with smaller diameter fills the tank alone in x hours.
Let the tap with larger diameter fills the tank alone in (x – 10) hours.
In 1 hour, the tap with smaller diameter can fill 1/x part of the tank.
In 1 hour, the tap with larger diameter can fill 1/(x – 10) part of the tank.
The tank is filled up in 75/8 hours.
Thus, in 1 hour the taps fill 8/75 part of the tank.
If x = 25, then (x – 10) = 25 – 10 = 15.
Thus, the tap with smaller diameter fills the tank alone in 25 hours where as the larger diameter fills the tank alone in 15 hours.
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